Answer to Koch Curve


N = 4 

S = 3 

D = 1.261 

P = infinity

A = (8/5) * Area at Level 0 (original equilateral triangle)

  = (8/5) * (sqrt(3)/4) * s^2   ( s = length of level 0 equilateral triangle)

  = ( 2 * sqrt(3) * s^2 )/ 5


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